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(H)=5+98H-4.9H^2
We move all terms to the left:
(H)-(5+98H-4.9H^2)=0
We get rid of parentheses
4.9H^2-98H+H-5=0
We add all the numbers together, and all the variables
4.9H^2-97H-5=0
a = 4.9; b = -97; c = -5;
Δ = b2-4ac
Δ = -972-4·4.9·(-5)
Δ = 9507
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-97)-\sqrt{9507}}{2*4.9}=\frac{97-\sqrt{9507}}{9.8} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-97)+\sqrt{9507}}{2*4.9}=\frac{97+\sqrt{9507}}{9.8} $
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